THE HORKE CAR

This is one of those curious and instructive riddles that can occur to us while we take a morning ride and that is able to feed our reflections still in the afternoon.

Recently, while walking with a friend in the country.

In the discussion that followed later, when we got home, there was such disparity of opinions between father and son about the world of traction, speed, turns and their relationship with the concept of dumping, which we did a practical experiment of which This riddle was born:

The drawing will help, not only to explain the nature of the riddle, but to trust in common sense and intuition when solving it, without throwing so much figures and rules of calculation of concentric circles.

Touring the car inside a ring of a certain diameter that we can establish as reasonably safe, it was found that the external wheels rotated twice for each turn of the inmates and that the wheels were separated by the usual distance of the 5 feet axis.

The problem is to find out the circumference of the route marked by the outer wheels when turning.

For the outer wheel to go twice faster than the interior, the circumference of that wheel must be twice as large as the other. As five feet are equivalent to half the radius of the outer wheel, the radius would be 10 feet, and the diameter of 20 feet.

3,1416 times 20 feet gives us 62,832, which is the circle of the circle described by the outer wheel.